35x^2+23x-12=0

Solution for 35x^2+23x-12=0 equation:

35x^2+23x-12=0

a = 35; b = 23; c = -12;
Δ = b2-4ac
Δ = 232-4·35·(-12)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-47}{2*35}=\frac{-70}{70}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+47}{2*35}=\frac{24}{70}
=12/35
$